{"localization":"No Remilot, it is not at all infeasible if we take into account the constraint of non-contact hanjies: no line touches another. To start: in C1 and C25 we can put crosses in L23, 24 and 25 because the 3 of these columns cannot touch the 2, 4 or 13 of these lines. So in L23 and L24, we see that 2 + 13 + 2 + 4 + 2 = 23 which is the number of boxes that remain to be completed. So (principle of alternation) they are placed in staggered rows starting with L23 since it contains one more line than L24. By putting the crosses along these lines, we place the 13 of L25 as well as the first and the last 1 of L21 which gives us the 3 of C1 and C25. Here, ask if you want the continuation.","ok":true}