{"localization":"Well. A helping hand: In C9 and C10 you find 2 pts on L9. As L1 only counts 1s, there will necessarily be at least 1 point of one of the two 9s on L10, which singularly limits the position of 5, therefore 11X to be placed on the end of L10, and 4X at the beginning. In C22, the 8 can only be found at the top. etc ...","ok":true}