Here is the last Hanjoku of this (nearly) diabolic serial.
Did you take notes ? You might do it (again?) this time.

Little anxiety : many hours spent on this game, imagine it, verify it on many ways. Let's hope that no error is detected (especially the dreaded typo !)

Be now ready to spend some time on this very hard step.
If you've solved the part 5/6, you obtained some datas : a list of 20 numbers.

With them, you have to determine the coordinates of 23 points (wich are black cells), let's call them P01 to P23). You'll then have to connect somme of them to obtain some diagonals, wich are usually impossible to find.

How to determine coordonates ?
Example : suppose that N25 is equal to 17, and that N28 is equal to 39.
In P27(N25/N28), you replace the two N by their value, you obtain then that P27 is L17C39.
Pay attention : sometimes you need to multiply, add or substract :
Examples : P31(2N29 / 3N24), P36(7+N27 / 1+N30), P45(N25+N26 / 11+N22), P50(N28-1 / N30)...

Here are the 23 points and the connections to do :
P01 (2N1 / N2) ; P02 (2N11 / N16) ; Connect P01 to P02.
P03 (2N4 / N8) , P04 (N10+N9 / N18) , P05 (N6+N17 / N5) , P06 (N14+N7 / N15+N3)
Connect P03 to P04 , P03 to P05 , P04 to P06.
P07 (N12+N7 / 3+N13) , P08 (N13+N3 / N17+N6) , Connect P07 to P08
P09 (N10 / N15+N2) , P10 (N12+N4 / N8+N9) , P11 (N13 / 2N2) , P12 (4+N11 / 3N15)
Connect P09 to P10 , P11 to P12 , P09 to P11 , P10 to P12.
P13 (2N3 / 3+N1) , P14 (1+N14 / 1+N18) , Connect P13 to P14
P15 (N4 / N5+N7) , P16 ( N18 / N16+N13) , P17 (N7 / 2N1) ; Connect P15 to P16, P15 to P17.
P18 (N7 / N14+N10) , P19 (2+N12 / 2N14)
These last two points are already connected (touching by a corner).
P20 (N19-6 / 8N20) , P21 (8N20 / N19-6) , P22 (10N20 / 2+N19) , P23 (2+N19 / 10N20)
Connect P20 to P21 , P20 to P23, P21 to P22 , P22 to P23.
Attention : in this last serial N19-6 is the number determined by N19 decreased by 6 and not N13.

If you have well connected your points, you obtained an oblique frame, with some parts of digits.

Except the 4 black cells wich are the corners of the frame and wich touch the external borders of the picross, there is no external element touching this frame, by side nor corner.

The same for inner the frame, except it's corners wich can be more or less blackened.
Each letter in the frame doesn't touch another one, by side nor corner.

Endly, in the bottom of the picross, there is an emoticon 9x9, whose frame doesn't touch any external or internal element, by side nor corner.
Considering its vertical axe, this emoticon is symetrical.

Now it's your turn. Have fun !